Volume of Rotation: Disk Method

There are two ways to think about the disk method.

Method A: Slice and Stack

You can think of just taking the area of a circle and then stacking that circle horizontally:

Slide the first radius dial: you'll see a yellow line extend from the x-axis to the function.

• Look at the face projection screen next to it: you see that this line becomes the radius of the circle. In the x-y plane, that is actually just the function itself.

Scroll the second slider: this rotates that radius around to sweep out a full circle of area pi * r².

Stack for volume: visualize stacking a bunch of these circular slices together from the start of the integral (a) to the end of the integral (b).

Method B: Revolve 2D Area

You can also think about it by first integrating the function itself (x² - 1) as you normally would, which gives you the 2D area underneath the curve:

• Revolve for volume: next, rotate that entire 2D area around the axis (multiplying by the circular circumference). You can see this by sliding the third slider.

• The formula: in the official format below, this is represented by the integral from a to b of f(x)² multiplied by pi. In the simulation to your right, f(x) is just the yellow radius line mapping from the x-axis to the function, representing the radius r.

Formula

V=πab[f(x)]2dxTextbook FormulaV=abπ(radius)2Area of a Circledx\begin{gathered} \underbrace{V = \pi \int_{a}^{b} [f(x)]^2 dx}_{\text{Textbook Formula}} \\ V = \int_{a}^{b} \underbrace{\pi ({\color{#eab308}\text{radius}})^2}_{\text{Area of a Circle}} dx \end{gathered}

Easy Example Problem

Find the volume of the solid generated by revolving the region under y = √x from x = 0 to x = 4 about the x-axis.

1. Identify the boundary limits: a = 0, b = 4.

2. The radius of rotation is f(x) = √x.

3. Set up the Disk Method integral:

V=π04(x)2dx=π04xdxV = \pi \int_{0}^{4} (\sqrt{x})^2 dx = \pi \int_{0}^{4} x dx

4. Integrate:

V=π[x22]04=π(1620)=8πV = \pi \left[ \frac{x^2}{2} \right]_{0}^{4} = \pi \left( \frac{16}{2} - 0 \right) = 8\pi
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