Volume of Rotation: Disk Method
The disk method finds the volume of a solid of revolution by integrating the area of circular cross-sections: volume equals pi times the integral from a to b of the radius squared, where the radius is the distance from the axis to the curve.
There are two ways to think about the disk method.
Method A: Slice and Stack
You can think of just taking the area of a circle and then stacking that circle horizontally:
• Slide the first radius dial: you'll see a yellow line extend from the x-axis to the function.
• Look at the face projection screen next to it: you see that this line becomes the radius of the circle. In the x-y plane, that is actually just the function itself.
• Scroll the second slider: this rotates that radius around to sweep out a full circle of area pi * r².
• Stack for volume: visualize stacking a bunch of these circular slices together from the start of the integral (a) to the end of the integral (b).
Method B: Revolve 2D Area
You can also think about it by first integrating the function itself (x² - 1) as you normally would, which gives you the 2D area underneath the curve:
• Revolve for volume: next, rotate that entire 2D area around the axis (multiplying by the circular circumference). You can see this by sliding the third slider.
• The formula: in the official format below, this is represented by the integral from a to b of f(x)² multiplied by pi. In the simulation to your right, f(x) is just the yellow radius line mapping from the x-axis to the function, representing the radius r.
What is the disk method formula for volume?
Disk method worked example: revolving the square-root curve
Find the volume of the solid generated by revolving the region under y = √x from x = 0 to x = 4 about the x-axis.
1. Identify the boundary limits: a = 0, b = 4.
2. The radius of rotation is f(x) = √x.
3. Set up the Disk Method integral:
4. Integrate:
Another worked example
Find the volume when the region under y = x from x = 0 to x = 2 is revolved about the x-axis. Step 1: the radius is x, so the cross-section area is pi times x squared. Step 2: integrate pi times x squared from 0 to 2. Step 3: the antiderivative is pi times x cubed over 3, giving pi times 8 over 3, which equals 8 pi over 3.
Aligned with the College Board AP Calculus CED — Unit 8 (Applications of Integration), Topic 8.9 (Volumes with Disks). College Board ↗
Interactive simulator is loading...
Engaged with the simulation?
Practice actual exam problems and master calculus guaranteed. Get a 5 on the AP Calculus exam or get an A in the calculus class, or we'll pay you $100.